Ok, so I always understood that W=V*A and given that, if you could convert a tool to 220V then the amps carried on each leg is cut in half. Given that, the wire sizes used does not have to be as large as it does for 110V. I saw a post (actually a few) on another forum that stated that was not true. Amps is amps whether it is 110 or 220V. There was no explanation given. One of the posters says he is an EE. So...
assuming I have a 100W light bulb that I can rewire for 220V. Plugging those values into our formula and solving for A we get:
100=110*A
100/110=A
1=A (or close enough)
Now using 220V:
100=220*A
100/220=A
.5=A(or close enough)
So what am I missing?
assuming I have a 100W light bulb that I can rewire for 220V. Plugging those values into our formula and solving for A we get:
100=110*A
100/110=A
1=A (or close enough)
Now using 220V:
100=220*A
100/220=A
.5=A(or close enough)
So what am I missing?
Comment