Very nice.
My first table
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The war against inferior and overpriced furniture continues!
ChrisComment
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COBOB,
The mortising was the greatest challenge to the piece. Remember when you sat in school and thought to yourself, "when the **** will I ever need to know that?" Well it all came home some 30 odd years later. Hold your breath...here it come...
The table was 24 inches on the back edge and 16 inches on the front edge and 28 inches deep. We'll call the mortise angles A at the back and and B at the front
Since all triangles have the sum of 180 deg of internal angles. And a right triangle can be made by removing the rectangle 16" X 28"
from the middle of the table, you are left with two right triangles, each with an 8 " base and a 28" height. The hypotenuse (long side of triangle) is calculated using the Pythagorean formula C squared= A squared + B squared. That yields C = 29.1 inches.
R cos (B) = X or 29.1 Cos (B) = 8.0 and Cos (B) = 0.275 Angle B = 74 degrees, Angle C = 90 Deg and by subtraction (the angle I needed) was Angle A =180 Deg - 164 Deg = 16 Deg.
So, by taking 1/2 the angle 16 degree angle for each end of the tenons ( because I was butting it up to the 90 degree angle on two sides of the legs) I was able to caculate the angle of my tenons to be 8 degrees.
I don't know which was more difficult, calculating the angle or cutting the angle, either way I am only building in squars from now on.
At this time I guess it would be most appropriate to thank my math professor Mr. Murray. I hope he is alive and well.
WingsComment
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Wow! That math made my nose leak blood... I get the Pythagorean Thereom, but the cosine and sine.... I think it would be less painful for me to just break one of the chairs so I could make a square table.COBOB,
The mortising was the greatest challenge to the piece. Remember when you sat in school and thought to yourself, "when the **** will I ever need to know that?" Well it all came home some 30 odd years later. Hold your breath...here it come...
The table was 24 inches on the back edge and 16 inches on the front edge and 28 inches deep. We'll call the mortise angles A at the back and and B at the front
Since all triangles have the sum of 180 deg of internal angles. And a right triangle can be made by removing the rectangle 16" X 28"
from the middle of the table, you are left with two right triangles, each with an 8 " base and a 28" height. The hypotenuse (long side of triangle) is calculated using the Pythagorean formula C squared= A squared + B squared. That yields C = 29.1 inches.
R cos (B) = X or 29.1 Cos (B) = 8.0 and Cos (B) = 0.275 Angle B = 74 degrees, Angle C = 90 Deg and by subtraction (the angle I needed) was Angle A =180 Deg - 164 Deg = 16 Deg.
So, by taking 1/2 the angle 16 degree angle for each end of the tenons ( because I was butting it up to the 90 degree angle on two sides of the legs) I was able to caculate the angle of my tenons to be 8 degrees.
I don't know which was more difficult, calculating the angle or cutting the angle, either way I am only building in squars from now on.
At this time I guess it would be most appropriate to thank my math professor Mr. Murray. I hope he is alive and well.
Wings
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