Your Age By Chocolate Math

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  • mater
    Veteran Member
    • Jan 2004
    • 4197
    • SC, USA.

    #1

    Your Age By Chocolate Math

    YOUR AGE BY CHOCOLATE MATH
    This is really, really neat!

    DON'T CHEAT BY SCROLLING DOWN FIRST!
    It takes less than a minute .
    Work this out as you read ...

    Be sure you don't read the bottom until you've worked it out! This
    is not one of those waste of time things, it's fun. Really!!



    1. First of all, pick the number of times a week that you would like
    to have chocolate (more than once but less than 10)

    2. Multiply this number by 2 (just to be bold)

    3. Add 5

    4. Multiply it by 50 -- I'll wait while you get the calculator.....

    5. If you have already had your birthday this year add 1756 ....
    If you haven't, add 1755.

    6. Now subtract the four digit year that you were born.
    You should have a three digit number.
    The first digit of this was your original number....(i.e., how many
    times you want to have chocolate each week).
    And this is the coolest part.....
    The next two numbers are
    YOUR AGE! (Oh YES, it is!!!!!)
    Ken aka "mater"

    " People may doubt what you say but they will never doubt what you do "

    Ken's Den
  • Popeye
    Veteran Member
    • Mar 2003
    • 1848
    • Woodbine, Ga
    • Grizzly 1023SL

    #2
    I'll be da.. .. .. .. ..d Pat
    Woodworking is therapy.....some of us need more therapy than others. <ZERO>

    Comment

    • Mrs. Wallnut
      Bandsaw Box Momma
      • Apr 2005
      • 1566
      • Ellensburg, Washington, USA.

      #3
      that is just too wierd.....but cool.
      Mrs. Wallnut a.k.a (the head nut).

      Comment

      • sacherjj
        Senior Member
        • Dec 2005
        • 813
        • Indianapolis, IN, USA.
        • BT3100-1

        #4
        C = number of times
        1 < C < 10
        50(2C + 5) + 1755(6) - YearBorn = 100C + Age
        100C + 250 + 1755(6) - YearBorn = 100C + Age
        2005(6) - YearBorn = Age.

        Yeah, that will always work for ages less that 100.
        Joe Sacher

        Comment

        • ironhat
          Veteran Member
          • Aug 2004
          • 2553
          • Chambersburg, PA (South-central).
          • Ridgid 3650 (can I still play here?)

          #5
          Originally posted by sacherjj
          C = number of times
          1 < C < 10
          50(2C + 5) + 1755(6) - YearBorn = 100C + Age
          100C + 250 + 1755(6) - YearBorn = 100C + Age
          2005(6) - YearBorn = Age.

          Yeah, that will always work for ages less that 100.


          What he said!!
          Blessings,
          Chiz

          Comment

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